Find the area under the standard normal probability distribution between the following pairs of z-scores. a. zequals0 and zequals1.00 e. zequalsminus1.00 and zequals0 b. zequals0 and zequals2.00 f. zequalsminus2.00 and zequals0 c. zequals0 and zequals3.00 g. zequalsnegative 1.49 and zequals0 d. zequals0 and zequals0.82 h. zequalsminus0.82 and zequals0
Accepted Solution
A:
Answer:See belowStep-by-step explanation:All this values can be easily found by using a table or a spreadsheet.
a)
P(0 ≤ z ≤ 1) = 0.3413
e)
P(-1 ≤ z ≤ 0) = P(0 ≤ z ≤ 1) = 0.3413 because N(0;1) is symmetrical
b)
P(0 ≤ z ≤ 2) = 0.4772
f)
P(-2 ≤ z ≤ 0) = P(0 ≤ z ≤ 2) = 0.4772
c)
P(0 ≤ z ≤ 3) = 0.4987
g)
P(-1.49 ≤ z ≤ 0) = 0.4319
d)
P(0 ≤ z ≤ 0.82) = 0.2939
h)
P(-0.82 ≤ z ≤ 0) = P(0 ≤ z ≤ 0.82) = 0.2939